GRAVITATIONAL
REDSHIFT ACCORDING TO THE
RECIPROCAL SYSTEM
If the frequency of a photon is f ’, at a location where the gravitational potential is GM/r, then according to Relativity the gravitational redshift is given by
where
The account of the gravitational redshift in the Reciprocal System may be given as follows: The gravitational motion of any material particle is inward in space, toward all other space-time locations. In a celestial object such as a star, which is an aggregate of such material units, this scalar inward motion of the individual units is counterbalanced by the physical continguity of the neighboring units. This counterbalancing force is in the scalar direction of the space-time progression, being opposite to gravity, and has the same magnitude as that of the gravitational motion at that location. Thus its measure is equal to the escape velocity, v. Now, we can identify the coordinate time increase at a particular location to be v²/c² (in fractions of units/unit), just like in the case of excess perihelion shift. This means that the total time involved per unit of clock-time is [1 + (v²/c²)] units. The frequency, f, denotes the number of oscillations per unit of time in a gravity-free situation. In the location under gravity, then, this frequency becomes f number of oscillations per [1 + (v²/c²)] units of time. Thus
Therefore, the redshift is
Comparison of the Results of the Two Theories The escape velocity, v, is evaluated as follows: The centrifugal force on a mass m rotating at the orbital speed of v at radius r is equal to the gravitational force by the central mass M, under equilibrium situation. Thus
Substituting this in eq. (1) and rearranging, we have, according to Relativity,
Comparing this
with eq (2) we can see that 1 - v²/c² »1
+ (v²/c²) |